You are not logged in.
Pages: 1
Topic closed
we have 3 pitches : 10 L , 7 L, 3 L .
we start with the 10 L full and we have to end up with the 10 containing 5 and the 7 containing 5 .
ye3ne:
10 7 3
1-10 0 0
2-5 5 0
have fun
huh didn't understand anything
you have to pass from 10 0 0 to 5 5 0 where the first number countains 10 , the second 7 and the third 3.And in 10 0 0 the first 1 is full and others empty. so you have to move from one reciepiant to another till u get to the state 5 5 0
OK that's how it goes.
u empty the 10 into the 7, and then the 7 into the 3 then the 3 back into the 10. So we've got 6 in the 10 and 4 in the 7.
We empty the 7 into the 3 and back in to the 10. Again the 7 into the 3. We we have 9 into the 10 and 1 in the 3.
We fill the 7 , and then empty the 7 into the 3. We are left with 5L into the 7, 2 into the 10 and 3 in the 3.
We emtpy the 3L into the 10 and we are set
Im sure there must be some easier method, but that's the first that came to my mind
Pages: 1
Topic closed